Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 48: 2.5a

Answer

$1.66\times10^{-24} g/amu$

Work Step by Step

We have: #g/amu = $\frac{1mol}{6.022\times10^{23}}\frac{1g/mol}{1amu/atom}$=$1.66\times10^{-24} g/amu$
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