Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 49: 2.25

Answer

$70.1$% $2.2$% $92.3$% $18.3$% $55.5$%

Work Step by Step

According to equation 2.16, we have: for MgO, $X_{Mg}=1.3$ and $X_{O}=3.5$ %$IC=[1-exp(-0.25)(3.5-1.3)^2]\times100=70.1$% for GaP, $X_{Ga}=1.8$ and $X_{P}=2.1$ %$IC=[1-exp(-0.25)(2.1-1.8)^2]\times100=2.2$% for CsF, $X_{Cs}=0.9$ and $X_{F}=4.1$ %$IC=[1-exp(-0.25)(4.1-0.9)^2]\times100=92.3$% for CdS, $X_{Cd}=1.5$ and $X_{S}=2.4$ %$IC=[1-exp(-0.25)(2.4-1.5)^2]\times100=18.3$% for FeO, $X_{Fe}=1.7$ and $X_{O}=3.5$ %$IC=[1-exp(-0.25)(3.5-1.7)^2]\times100=55.5$%
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.