Answer
$C_{Pb} $= 3.23 at%
$C_{Sn} $= 96.77 at%
Work Step by Step
Given:
5.5 wt% Pb
94.5 wt% Sn
Required:
atom in percent
Solution:
$A_{Pb} = 207.2 g/mol$
$A_{Sn} = 118.71 g/mol$
Using Equation 4.6,
$C_{Pb} = \frac{C_{Pb}A_{Sn}}{C_{Pb}A_{Sn} +C_{Sn}A_{Pb}} \times 100 = \frac{(5.5)(118.71 g/mol)}{(5.5)(118.71 g/mol) + (94.5)(207.2)} \times 100 $= 3.23 at%
$C_{Sn} =\frac{C_{Sn}A_{Pb}}{C_{Pb}A_{Sn} +C_{Sn}A_{Pb}} \times 100 = \frac{(94.5)(207.2 g/mol)}{(5.5)(118.71 g/mol) + (94.5)(207.2)} \times 100 $= 96.77 at%
