Discrete Mathematics and Its Applications, Seventh Edition

Published by McGraw-Hill Education
ISBN 10: 0073383090
ISBN 13: 978-0-07338-309-5

Chapter 1 - Section 1.2 - Applications of Propositional Logic - Exercises - Page 24: 43

Answer

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Work Step by Step

Note that there are six terms in the expression, two p's, q's, and r's. Four of these are negated, so we must put inverters after these (namely, p, r, q, and p). Now we have two subexpressions $\neg p\vee\neg r$ and $q \vee r$. So we need to add two "or" gates between the corresponding terms. The next subterms we need are the $\neg q$ and $\neg p$. Now we use two "and" gates to create the $(\neg p\vee\neg r)\wedge\neg q$ and $\neg p\wedge(q\vee r)$. Finally, we add an "or" gate between these two to create the final expression.
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