Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 1 - Foundations for Algebra - 1-2 Order of Operations and Evaluating Expressions - Practice and Problem-Solving Exercises - Page 13: 25

Answer

1728

Work Step by Step

The problem states to "evaluate each expression for s=4 and t=8," so we first plug in s=4 and t=8. This gives us: $(8+4)^{3}$. 8+4 is in parenthesis, so we consider it first, finding that 8 plus 4 is 12. We plug this in to obtain: $(12)^{3}=1728. $
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