Answer
$T'=\{ ...,-2,-1,0\}$
Work Step by Step
We have $U=\{ ...,-1,0,1,2,..12 \}$
and $T=\{ 1,2,3,...12 \}$
The complement of set T is the set of all elements in the universal set that are not in the set.
So $T'=\{ ...,-2,-1,0\}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 3 - Solving Inequalities - 3-5 Working With Sets - Practice and Problem-Solving Exercises - Page 198: 47
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