Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-2 Order of Operations and Evaluating Expressions - Practice and Problem-Solving Exercises - Page 14: 42

Answer

$$35/4$$

Work Step by Step

$$\frac{2[8+(67-2^6)^3]}{8}$$ $$PEMDAS: Parenthesis, Exponents, Multiply/Division, Addition/Subtraction$$ 1. Solve the exponent: $2^6$ $$2^6=2\times2\times2\times2\times2\times2=64$$ 2. Replace $2^6$ with $64$ $$\frac{2[8+(67-64)^3]}{8}$$ 3. Solve inner parenthesis: $(67-64)$ $$67-64=3$$ 4. Replace $(67-64)$ with $3$ $$\frac{2[8+(3)^3]}{8}$$ 5. Solve the exponent: $3^3$ $$3^3=3\times3\times3=27$$ 6. Replace $(3)^3$ with $27$ $$\frac{2[8+27]}{8}$$ 7. Solve bracket: $[8+27]$ $$8+27=35$$ 8. Replace $[8+27]$ with $35$ $$\frac{2[35]}{8}$$ 9. Simplify numerator: $2[35]$ $$2\times35=70$$ 10. Replace $2[35]$ with $70$ $$\frac{70}{8}$$ 11. Simplify fraction: $\frac{70}{8}$ $$\frac{70}{8}=\frac{35}{4}$$
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