Algebra 1

by Hall, Prentice

Published by Prentice Hall

ISBN 10: 0133500403

ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-2 Order of Operations and Evaluating Expressions - Standardized Test Prep - Page 15: 62

Answer

Work Step by Step

We substitute the values in. We have $(2(2))^{2}(4)-2(3)^{2}=4^{2}(4)-2(9)=16(4)-18=64-18=46$ To get the solution, follow PEMDAS by doing the parenthesis first, then exponents, then multiplication/division, and then addition/subtraction.

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