Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-3 Real Numbers and the Number Line - Practice and Problem-Solving Exercises - Page 20: 13

Answer

$\frac{6}{7}$

Work Step by Step

According to the textbook, a number, $a$, is a square root of another number, $b$, if $a^2=b$. $(\frac{6}{7})^2=\frac{36}{49}$, so $\frac{6}{7}$ is a square root of $\frac{36}{49}$. Therefore: $\sqrt {\frac{36}{49}}=\frac{6}{7}$
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