Algebra 2 (1st Edition)

by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee

Published by McDougal Littell

ISBN 10: 0618595414

ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - Guided Practice for Examples 2 and 3 - Page 516: 4

Answer

2.32

Work Step by Step

Since there is a variable in the exponent on one side of the equation, we use logarithms. Doing this, we find: $$ x = log_2 5 \\ x=2.32 $$

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