Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-5 Solving Inequalities - Practice and Problem-Solving Exercises - Page 40: 77

Answer

$y = \frac{9}{10}$

Work Step by Step

Subtract $3y$ from each side of the equation to isolate the variable to one side of the equation: $4y - 3y - \frac{1}{10} = 3y-3y+\frac{4}{5}$ Perform the subtraction: $y - \frac{1}{10} = \frac{4}{5}$ Add $\frac{1}{10}$ to each side to move constants to one side of the equation: $y = \frac{4}{5} + \frac{1}{10}$ To add fractions, we need to find the least common denominator (LCD) of both fractions. In this case, the LCD is $10$. We need to find equivalent fractions for both with denominators of 10: $y = \frac{8}{10} + \frac{1}{10}$ We can now add the fractions because they now have the same denominator: $y = \frac{9}{10}$
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