Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 48: 84

Answer

$x =\dfrac{ac + d}{ab}$ or $x =\dfrac{ac – d}{ab}$

Work Step by Step

First, isolate the absolute value by dividing both sides by $a$: $|bx – c| = \dfrac{d}{a}$ Separate the equation into its positive and negative cases (since $|x|=a \longrightarrow x=a \text{ or } x =-a$): $bx – c = \dfrac{d}{a}$ or $bx – c = –\dfrac{d}{a}$ Solve each equation for $x$ separately: $bx – c = \dfrac{d}{a}$ $bx = c + \dfrac{d}{a}$ $x =\dfrac{c + \frac{d}{a}}{b}$ or $bx – c = –\dfrac{d}{a}$ $bx = c – \dfrac{d}{a}$ $x =\dfrac{c – \frac{d}{a}}{b}$ So our answer is $x =\dfrac{c + \frac{d}{a}}{b}$ or $x =\dfrac{c – \frac{d}{a}}{b}$ We could also simplify these by multiplying numerator and denominator by a, then we’d have: $x =\dfrac{ac + d}{ab}$ or $x =\dfrac{ac – d}{ab}$
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