Answer
The point (2,0) lies on the graph of $y=x^2-3x+2$, but the point (-2,8) does not.
Work Step by Step
$y=x^2-3x+2$
(a) Point: (2,0):
$0=2^2-3(2)+2$
$0=4-6+2$
$0=0$
Correct.
(b) Point: (-2,8):
$8=(-2)^2-3(-2)+2$
$8=4+6+2$
$8=12$
Incorrect.
