Answer
false
Work Step by Step
$x=2$ cannot be a solution because the denominator cannot be $0$. Let's multiply both sides by $x-2$, then: $2(x-2)-1=3\\2(x-2)=4\\x-2=2\\x=4$
Thus $x=4$ is a good solution, so the statement is false.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.2 - Linear Equations in One Variable - 1.2 Exercises - Page 89: 78
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