Answer
$8n^{2} + 8n + 4$
Work Step by Step
If the first even is 2n, the next is 2n+2. The sum of their squares is:
$(2n)^{2} + (2n+2)^{2} = $ = $4n^{2} + 4n^{2} + 8n + 4$ = $8n^{2} + 8n + 4$
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