Answer
$a_n=\frac{2^{n-1}}{3^n}$
Work Step by Step
The numerator starts at $1$ and gets multiplied by $2$ at each term, and the denominator starts at $3$ and gets multiplied by $3$ at each term. Thus a general term is $a_n=\frac{2^{n-1}}{3^n}$.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 46
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