Answer
$h = \sqrt {d^2 - 3000^2}$, $d \geq 3000$
Work Step by Step
Use the Pythagarean theorem.
$h^2 + 3000^2 = d^2$
$h = \sqrt {d^2 - 3000^2}$
Expression under the square root should be non-negative.
$d^2 - 3000^2 \geq 0$
$d \geq 3000$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 185: 69b
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