Answer
(a) $2\sqrt 5$
(b) $4\sqrt[3] 2$
Work Step by Step
(a) $\sqrt {20}=\sqrt {4\times5}=\sqrt {2^2\times5}=2\sqrt 5$
(b) $\sqrt[3] {128}=\sqrt[3] {64\times2}=\sqrt[3] {2^6\times2}=2^2\sqrt[3] 2=4\sqrt[3] 2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 25: 43
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