Answer
$x^2+2x+1-2xy-2y+y^2$
Work Step by Step
Using the special product of a binomial formula
$(u+v)^2=u^2+2uv+v^2$,
$[(x+1)-y]^2$
$=(x+1)^2-2(x+1)y+y^2$
$=x^2+2x+1-2xy-2y+y^2$
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