Answer
$\frac{5}{8}[(x+3)^2-16]$
Work Step by Step
$Area~of~the~large~triangle-Area~of~the~small~triangle=\frac{1}{2}\frac{5}{4}(x+3)(x+3)-\frac{1}{2}(5)(4)=\frac{5}{8}(x+3)^2-10=\frac{5}{8}[(x+3)^2-16]$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.4 - Factoring Polynomials - Exercises - Page 40: 82
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