Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - Review Exercises - Page 62: 16

Answer

(a) $\frac{1}{2}$ (b) It is not possible because we can not perform a division in which the denominator is equal to 0.

Work Step by Step

$\frac{x}{x-3}$ (a) $x=-3$ $\frac{-3}{-3-3}=\frac{-3}{-6}=\frac{1}{2}$ (b) $x=3$ $\frac{3}{3-3}=\frac{3}{0}$. It is not possible.
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