Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.2 - Solving Multi-Step Equations - Monitoring Progress - Page 13: 5

Answer

$d=\frac{11}{4}$

Work Step by Step

$$\begin{align*} 15-5&=5+4(2d-3)-5 &\text{Subtract 5 from each side.}\\ 10&=4(2d-3) &\text{Simplify.}\\ \frac{10}{4}&=\frac{4(2d-3)}{4} &\text{Divide 4 to both sides.}\\ \frac{5}{2}&=2d-3 &\text{Simplify.}\\ \frac{5}{2}+3&=2d-3+3 &\text{Add 3 to both sides.}\\ \frac{11}{2}&=2d &\text{Simplify.}\\ \frac{\frac{11}{2}}{2}&=\frac{2d}{2} &\text{Divide 2 to both sides.}\\ \frac{11}{4}&=d \end{align*}$$ Check the answer by substituting $\frac{1}{4}$ to the variable $d$ in the given equation. $$\begin{align*} 15&=5+4(2d-3)\\ 15&\stackrel{?}{=}5+4\left[2\cdot\frac{11}{4}-3\right]\\ 15&\stackrel{?}{=}5+2\cdot11-12\\ 15&\stackrel{\checkmark}{=}15 \end{align*}$$ Thus, the solution is $d=\frac{11}{4}$.
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