Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - 1.4 - Solving Absolute Value Equations - Monitoring Progress - Page 29: 6

Answer

$x=1$ and $x=-\frac{3}{5}$

Work Step by Step

The given equation is $\Rightarrow -2|5x-1|-3=-11$ Add $3$ to each side. $\Rightarrow -2|5x-1|-3+3=-11+3$ Simplify. $\Rightarrow -2|5x-1|=-8$ Divide each side by $-2$. $\Rightarrow \frac{-2|5x-1|}{-2}=\frac{-8}{-2}$ Simplify. $\Rightarrow |5x-1|=4$ Write related linear equations. $\Rightarrow 5x-1=4$ or $5x-1=−4$ Add $1$ to each side. $\Rightarrow 5x-1+1=4+1$ or $5x-1+1=−4+1$ Simplify. $\Rightarrow 5x=5$ or $5x=−3$ Divide each side by $5$. $\Rightarrow \frac{5x}{5}=\frac{5}{5}$ or $\frac{5x}{5}=−\frac{3}{5}$ Simplify. $\Rightarrow x=1$ or $x=−\frac{3}{5}$ Check $x=1$ $\Rightarrow -2|5(1)-1|-3=-11$ $\Rightarrow -2|5-1|-3=-11$ $\Rightarrow -2|4|-3=-11$ $\Rightarrow -2(4)-3=-11$ $\Rightarrow -8-3=-11$ $\Rightarrow -11=-11$ True. Check $x=-\frac{3}{5}$ $\Rightarrow -2|5(-\frac{3}{5})-1|-3=-11$ $\Rightarrow -2|-3-1|-3=-11$ $\Rightarrow -2|-4|-3=-11$ $\Rightarrow -2(4)-3=-11$ $\Rightarrow -8-3=-11$ $\Rightarrow -11=-11$ True. Hence, the solutions are $x=1$ and $x=-\frac{3}{5}$.
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