Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - Monitoring Progress - Page 2: 1

Answer

There was a population increase of $3$ million per year from $2000$ to $2010.$

Work Step by Step

Determine the increase (or decrease) in population by subtracting the population in $2000$ from the population in $2010$: $310\text{ million} - 280\text{ million} = 30\text{ milllion}$ Determine the time elapsed (in years) by subtracting $2000$ from $2010$: $2010 - 2000 = 10\text{ years}$ There was a $30$ million increase in population in $10$ years. Determine the annual rate of change by dividing $10$ to the increase in population to obtain: $\text{annual rate of change}=\dfrac{30\text{ million}}{10\text{ years}}=3\text{ million per year}$ Therefore, the annual rate of change in the population from $2000$ to $2010$ was $3$ million.
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