College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises - Page 85: 44

Answer

$h=\frac{2A}{B+b}$

Work Step by Step

Multiply both sides by 2 and divide by $(B+b)$. $2A=h(B+b)$ $\frac{2A}{B+b}=h$ $h=\frac{2A}{B+b}$
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