College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Exercises - Page 86: 70

Answer

$82.6^{\circ}F$

Work Step by Step

Use the formula $F=\frac{9}{5}C+32$ and substitute $28.1$ to $C$ to otbain: $F = \frac{9}{5}C +32$ $F = \frac{9}{5}(28.1) + 32$ $F = 50.58 +32$ $F = 82.58$ $F \approx 82.6$
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