College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Review Exercises - Page 77: 123

Answer

$\dfrac{1}{(-2)^3} = \dfrac{1}{-8}$

Work Step by Step

The error was that the negative sign on the denominator was incorrectly moved to the exponent. Hence, $\dfrac{1}{(-2)^3}=\dfrac{1}{-8}$
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