College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.4 - Factoring Polynomials - R.4 Exercises - Page 38: 31

Answer

2a(2a - 3)(3a + 7)

Work Step by Step

1. Factor out GCF: 2a(6$a^{2}$ + 5a - 21) 2. Factor expression inside parentheses: 2a(2a - 3)(3a + 7) 3. Check: 2a(2a - 3)(3a + 7) = 12$a^{3}$ + 10$a^{2}$ - 42a
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