College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.3 - Page 255: 83

Answer

$y$-intercept $=5$

Work Step by Step

Point on a line: $(3,-1)$ $;$ Line's slope: $-2$ Obtain the $y$-intercept. Do so by obtaining the line's equation. The point-slope form of the equation of a line is $y-y_{1}=m(x-x_{1})$, where $m$ is the slope of the line and $(x_{1},y_{1})$ is a point through which it passes. Both $m$ and $(x_{1},y_{1})$ are given, so substitute them into the point-slope form of the equation of a line formula and simplify: $y-y_{1}=m(x-x_{1})$ $y-(-1)=-2(x-3)$ $y+1=-2x+6$ Solve for $y$: $y=-2x+6-1$ $y=-2x+5$ The equation is now in slope-intercept form and according to that form, which is $y=mx+b$, $b$ is the $y$-intercept of the line. In this case, it can be seen that $b=5$, so the $y$-intercept of the line is $(0,5)$
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