Answer
f(x)=2(x+10)$^2$-5
Work Step by Step
The given function has its vertex at 0. To move the vertex to (-10,-5) you must subtract negative ten from x and add negative five to the function. This gives you f(x)=2(x+10)$^2$-5.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.1 - Page 344: 51
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