Answer
$x=0, x\approx1.61$
Work Step by Step
Factor by using trial and error, and then use the natural logs to solve for $x$.
$e^{2x}-6e^x+5=0$
$(e^x-5)(e^x-1)=0$
$e^x=5, e^x=1$
$x=0, x\approx1.61$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Summary, Review, and Test - Test - Page 513: 14
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
