College Algebra (6th Edition)

by Blitzer, Robert F.

Published by Pearson

ISBN 10: 0-32178-228-3

ISBN 13: 978-0-32178-228-1

Chapter 5 - Mid-Chapter Check Point - Page 562: 18

Answer

See below.

Work Step by Step

Let $x$ be the number of roses, then the number of canatations is $20-x$, thus the total cost is: $3x+1.5\cdot(20-x)=39\\3x+30-1.5x=39\\1.5x=9\\x=6$ Thus we have $6$ roses and $20-6=14$ carnatations.

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