Answer
$44$
Work Step by Step
$\sum_{i=1}^{4} (i+4)(i-1)=((1+4)(1-1))+((2+4)(2-1))+((3+4)(3-1))+((4+4)(4-1))=5\cdot0+6\cdot1+7\cdot2+8\cdot3=0+6+14+24=44$
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