Answer
The ball's height 2 seconds after it was kicked is 60 feet.
Work Step by Step
A football was kicked vertically upward from a height of 4 feet with an initial speed of 60 feet per second. The formula $$h=4+60t-16t^{2}$$ describes the ball's height above the ground, h, in feet, t seconds after it was kicked.
What was the ball's height 2 seconds after it was kicked?
2 seconds represents the time, t, so substitute the 2 for each t in the equation:$$h=4+60(2)-16(2)^{2}$$
Work exponents first:$$h=4+60(2)-16(4)$$
Figure all division and multiplication next (in order left to right):$$h=4+120-64$$
Then complete all addition and subtraction in order left to right:$$h=124-64$$$$h=60$$
