College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 89: 1

Answer

Evaluating $3+6(x-2)^{3}$ for $x=4$ gives $51$

Work Step by Step

Evaluate $3 + 6(x - 2)^{3}$ if x = 4. Let's substitute the value of x in the given expression. if x = 4 =$3 + 6(4 - 2)^{3}$ Apply the PEMDAS rule: Perform the operation inside the parentheses =$3 + 6(4 - 2)^{3}$ =$3 + 6(2)^{3}$ Next, Expand the exponent =$3 + 6(2· 2· 2)$ =$3 + 6(8)$ Then, Multiply 6 and 8 =$3 + 6(8)$ =$3 + 48$ To find the final answer. Just add 3 and 48. =$3 + 48$ =$51$ Therefore, $3 + 6(x - 2)^{3}$ if x = 4 gives 51.
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