Answer
$\frac{y^8}{4x^{10}}$
Work Step by Step
Use the rule of exponents to divide the exponents by subtracting them, and divide the regular numbers to simplify. Then put negative exponents back in the denominator.
$\frac{7x^5y^6}{28x^{15}y^{-2}}$
$\frac{7}{28}*x^{5-15}y^{7-(-2)}$
$\frac{1}{4}x^{-10}y^8$
$\frac{y^8}{4x^{10}}$
