Answer
$x^2$
Work Step by Step
The given radical can be written as:
$=\sqrt[5]{(x^2)^5}$
RECALL:
(i) $\sqrt[n]{a^n} = |a|$ when $n$ is even
(ii) $\sqrt[n]{a^n} = a$ when $n$ is odd
The given radical has n=5, which is even.
Use rule (ii) above, where $a=x^2$, to obtain:
$\sqrt[5]{(x^2)^5}=x^2$