Answer
c$^2$+2+$\frac{1}{c^2}$
Work Step by Step
(A+B)$^2$=A$^2$+2AB+B$^2$
(c+$\frac{1}{c}$)$^2$
(c)$^2$+2(c)($\frac{1}{c}$)+($\frac{1}{c}$)$^2$
c$^2$+2($\frac{c}{c}$)+$\frac{1}{c^2}$
c$^2$+2+$\frac{1}{c^2}$
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