College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 44: 121

Answer

See the proof below.

Work Step by Step

By doing the term-by-term multiplication and then canceling the terms, we get: a) $(A-B)(A^2+AB+B^2)=A^3+A^2B+AB^2-BA^2-AB^2-B^3=A^3-B^3$ b) $(A+B)(A^2-AB+B^2)=A^3-A^2B+AB^2+BA^2-AB^2+B^3=A^3+B^3$ Thus, we proved what we had to in both cases by expanding the right-hand side as required.
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