College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises - Page 60: 34

Answer

$ \displaystyle y=\frac{21}{11}$

Work Step by Step

$\displaystyle \frac{2}{3}y+\frac{1}{2}(y-3)=\frac{y+1}{4}$ We multiply by 12: $8y+6(y-3)=3(y+1)$ And distribute: $8y+6y-18=3y+3$ And simplify: $14y-18=3y+3$ And combine $y$ terms: $11y=21$ And solve for $y$: $ \displaystyle y=\frac{21}{11}$
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