Answer
$2n^{2}+2n+1$
Work Step by Step
$n$ = the first integer
$n+1$ = the second integer
Thus the sum of their squares is:
$n^{2}+(n+1)^{2}=n^{2}+(n^{2}+2n+1)=2n^{2}+2n+1$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Section P.9 - Modeling with Equations - P.9 Exercises - Page 70: 10
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