College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.9 - Modeling with Equations - P.9 Exercises - Page 72: 47

Answer

$200$ mL

Work Step by Step

Let $x$ be the amount of $60\%$ solution, then the amount of $30\%$ solution is $300-x$. Then our equation is: $x\cdot0.6+(300-x)0.3=300\cdot0.5\\0.6x+90-0.3x=150\\0.3x=60\\x=200$
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