Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 6 - Linear Transformations - 6.3 The Kernel and Range of a Linear Transformation - Problems - Page 405: 2

Answer

See below

Work Step by Step

Given: $A=\begin{bmatrix} 1 & -1 & 2\\ 1 & -2 & -3 \end{bmatrix}$ Let $x=(x_1,x_2,x_3) \in R^3$ we obtain: $\begin{bmatrix} 1 & -1 & 2\\ 1 & -2 & -3 \end{bmatrix}\begin{bmatrix} x_1\\ x_2\\ x_3 \end{bmatrix}=\begin{bmatrix} x_1-x_2+2x_3\\ x_1-2x_2-3x_3 \end{bmatrix} \\ T(x_1,x_2,x_3)=(x_1-x_2+2x_3,x_1-2x_2-3x_3)$ a) $x=(7,5,-1)$ $T(7,5,-1)=(7-5+2(-1),7-2.5-3(-1))=(0,0) \\ \rightarrow x \in Ker(T)$ b) $x=(-21,-15,2)$ $T(-21,-15,2)=(-21-(-15)+2(2),-21-2.(-15)-3(2))=(-2,3) \\ \rightarrow x \notin Ker(T)$ c) $x=(35,25,-5)$ $T(35,25,-5)=(35-25+2(-5),35-2.(25)-3(-5))=(0,0) \\ \rightarrow x \in Ker(T)$
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