Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 6 - Linear Transformations - 6.4 Additional Properties of Linear Transformation - Problems - Page 419: 44

Answer

See below

Work Step by Step

We are given $\{w_1,w_2...,w_m\}$ spans $W \rightarrow w \in W$ (1) Let $\alpha_1,\alpha_2,...,\alpha_m$ be scarlars such as: $$\alpha_1v_1+\alpha_2v_2+....+a_mv_m=0 \\ \rightarrow \alpha_1=\alpha_2=...=\alpha_m=0$$ Let: $$w=\alpha_1 T(v_1),\alpha_2T(v_2),...,\alpha_mT(v_m) \\ w=T(\alpha_1(v_1)+\alpha_2(v_2)+...+\alpha_mv(v_m)) $$ Since $V$ is a vector space and $v_1,v_2....,v_m \in V \\ \rightarrow \alpha_1 v_1+\alpha_2 v_2+...+\alpha _mv_m \in V\\ \rightarrow v \in V$ (2) From(1) and (2), we have $T(v)=w $ Hence $T$ is onto.
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