Answer
The linear transformation in Problem 1 is not invertible.
Work Step by Step
From Exercise 1, we have:
$T^C_B=\begin{bmatrix}
1 & 0 & 0 & -1\\
0 & 0 & 0 & 0\\
0 & 3 & 0 & 0\\
-1 & 0 & 1 & 0
\end{bmatrix}$
From the second row, $\det (T^C_B)=0$
Hence, $T^C_B$ is not invertible matrix.