Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 7 - Eigenvalues and Eigenvectors - 7.2 General Results for Eigenvalues and Eigenvectors - Problems - Page 452: 19

Answer

See below

Work Step by Step

1. Find eigenvalues: (A-$\lambda$I)$\vec{V}$=$\vec{0}$ $\begin{bmatrix} 1-\lambda & -3 & 1 \\ -1 & -1-\lambda & 1 \\ -1 & -3 & 3-\lambda \end{bmatrix}\begin{bmatrix} v_1\\ v_2 \\ v_3 \end{bmatrix}=\begin{bmatrix} 0\\ 0 \\ 0 \end{bmatrix}$ $\begin{bmatrix} 1-\lambda & -3 & 1 \\ -1 & -1-\lambda & 1 \\ -1 & -3 & 3-\lambda \end{bmatrix}=0$ $-( \lambda -2)^2(\lambda +1)=0$ $\lambda_1=2 + 3i, \lambda_2=-2-3i$ $\dim =1 \ne 2$ Hence, matrix $A$ is non-defective.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.