Answer
See below
Work Step by Step
We have $sum A=0+2+1+(-2)=1$
We obtain reduced row echelon matrix form:
$\begin{bmatrix}
-1 & 1 & 1 & 1\\
0 & -3 & 1 & 1 \\
0 & 0 & \frac{19}{3} & -\frac{2}{3} \\
0 & 0 & 0 & \frac{69}{19}
\end{bmatrix}$
Product of the given matrix is: $\det (A)=
(-1)^3.69\\
=-69$