Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.1 - Numerical and Algebraic Expressions - Problem Set 1.1 - Page 8: 73

$36 + (12 \div 3) + 3 + (6 \times 2) = 55$

Complete the orders inside the parenthesis first. Divide $12 \div 3 = 4$ and then multiply $6 \times 2 = 12$ first. Then simply add all the numbers. $36 + 12 \div 3 + 3 + 6 \times 2 = 55$ $36 + (12 \div 3) + 3 + (6 \times 2) = 55$ $36 + 4 + 3 + 12 = 55$ $40 + 3 + 12 = 55$ $40 + 15 = 55$ $55 = 55$