Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - 1.3 - Integers: Addition and Subtraction - Problem Set 1.3 - Page 20: 98

$= 8$

1. We first substitute the x, y, and z values into the equation using parenthesis: $-x - y - z$ for $x = 12$, $y = -6$, $z = -14$ $= -(12)- (-6) - (-14)$ 2. A double negative such as "−(−6)" will cancel out to become "6", a positive number. $= -12 + 6 + 14$ $= -12 + 20$ $= 20 - 12$ $= 8$