Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - Chapter 1 Review Problem Set - Page 38: 58

$1$

Substituting $x= -4 $ and $y= -6 $, the given expression, $ \dfrac{-3x+4y}{3x} ,$ evaluates to \begin{array}{l}\require{cancel} \dfrac{-3(-4)+4(-6)}{3(-4)} \\\\= \dfrac{12-24}{-12} \\\\= \dfrac{-12}{-12} \\\\= 1 .\end{array}